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CBSE Class 12-science Answered

solve image question  
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Asked by uv526387 | 19 Oct, 2020, 07:33: PM
answered-by-expert Expert Answer
Part-(a)
 
Magnitude of electrostatic force F between tw spheres 
 
begin mathsize 14px style F space equals space K space cross times fraction numerator q subscript 1 q subscript 2 over denominator r squared end fraction space equals space fraction numerator 9 space cross times 10 to the power of 9 cross times 0.4 cross times 10 to the power of negative 6 end exponent space cross times 0.8 space cross times 10 to the power of negative 6 end exponent over denominator r squared end fraction space equals space 0.2 space N end style
where K = 1/ ( 4 π εo ) = 9 × 109 is Coulomb's constant , q's are charge magnitudes on sphere
and r is distance between centres of spheres.
 
begin mathsize 14px style r space equals space square root of fraction numerator 9 cross times 10 to the power of negative 3 end exponent cross times 0.4 cross times 0.8 over denominator 0.2 end fraction end root space equals space 0.12 space m space equals space 12 space c m end style
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Part-(b)
 
Force on second sphere due to first sphere is same as the force on first sphere due to second sphere.
 
One sphere has +ve charge and other has -v charge, both have equal attractive force towards other
Answered by Thiyagarajan K | 19 Oct, 2020, 08:08: PM

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