JEE Class main Answered
solve all the three paragraph questions in detail
Asked by sarveshvibrantacademy | 11 May, 2019, 11:58: AM
Expert Answer
At steady state we have the heat conduction equation across the piston , q = k A (dT/l) = k A (T-T0)/l .......................(1)
where q is steady state heat flux, k is thermal conductivity of material of piston, A is area of piston,
T0 is initial temperature and T is final temperature.
we rewrite eqn.(1) as T = T0 + ql/(kA) .................(2)
Qn.(3)
initially heat flux q = 0 and steadily it is increasing to reach constant value.
Hence Temperature of enclosed gas steadily increasing staring from T0 and reaching steady state value T as shown in fig.(B)
Qn(4) maximum temperature is as given in eqn.(2)
Qn.(5) since otherside of piston at atmospheric pressure, pressure of the enclosed gas is constant.
For ideal gas at constant pressure, we have V/T = constant, where V is volume.
hence V/V0 = T/T0 .........................(3)
by dividing both side of eqn.(2) by T0 we get ( T/T0 ) = 1 + [ ql/(k A T0) ] = V/V0
Answered by Thiyagarajan K | 11 May, 2019, 04:26: PM
Application Videos
JEE main - Physics
Asked by sandhyapallapu22 | 03 May, 2024, 04:32: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by gamingbadboy085 | 01 May, 2024, 06:28: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by bhargavreddynellaballi | 30 Apr, 2024, 08:18: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ravichandraravula66 | 29 Apr, 2024, 11:20: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by kmani310507 | 28 Apr, 2024, 04:38: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by arivaryakashyap | 23 Apr, 2024, 10:40: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ratnadeep.dmr003 | 21 Apr, 2024, 11:06: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ksahu8511 | 19 Apr, 2024, 11:55: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by mohammedimroz | 13 Apr, 2024, 09:48: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by medhamahesh007 | 02 Apr, 2024, 11:11: AM
ANSWERED BY EXPERT