JEE Class main Answered
Sir, pls solve the following.
Asked by rsudipto | 23 Dec, 2018, 09:08: AM
Expert Answer
xyz = 24 = 2 × 2 × 3 × 2
Consider x, y, z, 3 can be put in any of the three boxes.
also, 2, 2, 2 can be distributed in the three boxes in 3 + 3 - 1C3 - 1 = 5C2 ways.
The total number of integral solutions is equal to the number of positive integral solutions is equal to 3 × 5C2 = 30
To find integral solutions where negative integrals are allowed.
Any two of the three can be negative.
The number of ways to associate negative sign in each case 3C2 = 3
Hence, the number of integral solutions 30 + 3 × 30 = 120
Answered by Sneha shidid | 24 Dec, 2018, 10:51: AM
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