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It is assumed that the expression " 2(α+β+γ+δ) = 8 " has to be proved.

Intersection point of diagonals is mid point of each diagonal.

Hence using midpoint formula for AC , we get the coordinates of midpoint as [ (α+γ) / 2 ,  ( β+δ ) / 2 ] .

Hence using midpoint formula for DB , we get the coordinates of midpoint as [ 1 ,  1 ] .

Since the mid points of both diagonals coincident, we equate the midpoints to get the values of (α+γ) and ( β+δ ) .

Then , it is proved that " 2(α+β+γ+δ) = 8 "