JEE Class main Answered
Sir pls solve the following.
Asked by rsudipto | 02 Jan, 2019, 19:40: PM
Expert Answer
Electric field between the plates would be E=V/d = 600/3×10^-3 = 2×10^5
For electron to pass with any deviation force due to magnetic field as well due to electric field must be equal
So qvB= we
2×10^6×B =2×10^5
B = 0.1 T.
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