Sir please explain me , how to derive upthrust=v*d*g mathematically..
Asked by Himadri | 26th Sep, 2019, 02:08: PM
- Let us consider a cylindrical body PQRS of cross-sectional area A. It is immersed in a liquid of density ρ.
- The upper surface is at a depth of h1 and the lower surface is at a depth of h2.
- The pressure on the upper surface is P1 = h1ρg. Thus, the downward thrust on the upper surface is
- The pressure on the lower surface is P2 = h2ρg. Thus, the upward thrust on the lower surface is
F2 = h2ρgA
- Since h2 > h1, we have F2 > F1.
- Thus, the resultant upward thrust, i.e. the buoyant force, is
Fb = F2 - F1
Fb = h2ρgA - h1ρgA = (h2 - h1) ρgA = Vρg
Answered by Shiwani Sawant | 26th Sep, 2019, 06:42: PM
- What is upthrust
- respected sir i request you to please explain me this characteristic property of buoyancy:-[given my school module] the upthrust acts on the body in upward direction at the centre of buoyancy i.e. the centre of gravity of the displaced liquid
- Why there is no change in level of water on melting of floating piece of ice
- Respected Sir/Madam actually i am not understanding the video of archmedes principle lesson of relative density part.So that can you pls make another video and upload it
- A body whose volume is 100cm^3 weighs 1kgf in air. Find its weight in water.
- What is the cause of upthrust ? At which point it can be considered to act ?
- Can you do a video class of Archimedes principal and floatation
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