CBSE Class 10 Answered
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Sum of all integers between 100 and 500 which are divisible by 17
Asked by seeni2005 | 17 Aug, 2020, 12:42: AM
Expert Answer
The first and last numbers between 100 and 500 which are divisible by 17 are 102 and 493.
The numbers divisible by 17 forms an AP with common difference d=17, first term a = 102 and last term an = 493
an = a + (n-1)d
493 = 102 + (n-1)17
(n-1)17 = 391
n-1 = 23
n = 24
Now, the formula for sum of n terms of an AP can be used to find the required sum
Answered by Renu Varma | 17 Aug, 2020, 12:19: PM
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