CBSE Class 11-science Answered
sin(90+θ)*.tan(270-θ)*.cot(360-θ)/cot(-θ)*.tan(90+θ)*.cos(180+θ)=
Asked by nayaktapaswini2007 | 29 Feb, 2024, 09:10: AM
Expert Answer
............................(1)
sin(90+θ) = cosθ ;
tan(270-θ) = sin(270-θ) / cos(270-θ) = -cosθ / -sinθ = cotθ
cot(360-θ) = cos(360-θ)/sin(360-θ) = cosθ /-sinθ = -cotθ
tan(90+θ) = sin(90+θ) / cos(90+θ) = cosθ / -sinθ = -cotθ
cos(180+θ) = -cos θ
Hence eqn.(1) is written as
Answered by Thiyagarajan K | 29 Feb, 2024, 03:49: PM
Concept Videos
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Sign of Trigonometric Functions
This video covers values of trigonometric ratios of angles greater than 90 ... -
Sign of Trigonometric functions
This video covers values of trigonometric ratios of angles greater than 90 ... -
Sign of Trigonometric functions
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