Asked by thajvirkaur | 28th Jan, 2012, 07:41: AM
in question it is not specified whether all charges lie in straight line or not but for simplification we are taking them in straight line.
FAB is the force exerted on charge at B due to charges on A.
direction is away from point A as both the charges are positive and hence their exist a repulsive force.
FBC is the force exerted on charge at B due to charge on c.
direction is away from point C as both the charges are positive and hence their exist a repulsive force.
we can calculate these force by formula:
F = 1/4?? ( q1*q2/r2)
FAB = 1/4?? (3q2/x2)
FBC = 1/4?? (4q2/x2)
and resulting force is FR= FBC- FAB = 1/4?? (4q2/x2) - 1/4?? (3q2/x2) = 1/4?? (q2/x2)
and resulting force would be towards direction of FBC because magnitude of FBC is greater than FAB.
Answered by | 29th Jan, 2012, 07:21: PM
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