CBSE Class 10 Answered
Quadratic Equations
Asked by toppin | 11 Jan, 2010, 10:01: PM
Expert Answer
x = [-B±
(B2-4AC)]/2A
A = 4
B = -2(a2+b2)
C = a2b2
x = [2(a2+b2)±(4(a2+b2)2 - 16a2b2)]/8
= [2(a2+b2)±2((a2+b2)2 - 4a2b2)]/8
= [2(a2+b2)±2(a2-b2)2]/8
Hence x = a2/2 or b2/2
Regards,
Team,
TopperLearning.
Answered by | 11 Jan, 2010, 10:40: PM
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