Quadratic Equations

Asked by toppin | 11th Jan, 2010, 10:01: PM

Expert Answer:

x = [-B±(B2-4AC)]/2A

A = 4

B = -2(a2+b2)

C = a2b2

x = [2(a2+b2(4(a2+b2)2 - 16a2b2)]/8

= [2(a2+b2)±2((a2+b2)2 - 4a2b2)]/8

= [2(a2+b2)±2(a2-b2)2]/8

Hence x = a2/2 or b2/2

Regards,

Team,

TopperLearning.

 

 

 

Answered by  | 11th Jan, 2010, 10:40: PM

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