Prve that

Asked by  | 22nd May, 2009, 06:49: PM

Expert Answer:

L.H.S=sinA/(1-sinA/cosA)+sinA/(1-cosA/sinA)

=sinAcosA/(cosA-sinA)+sin2A/(sinA-cosA)

=(sinAcosA-sin2A)/(cosA-sinA)

=sinA(cosA-sinA)/(cosA-sinA)

=sinA=R.H.S (make correction in problem statement)

Answered by  | 23rd May, 2009, 03:41: PM

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