Prve that
Asked by | 22nd May, 2009, 06:49: PM
Expert Answer:
L.H.S=sinA/(1-sinA/cosA)+sinA/(1-cosA/sinA)
=sinAcosA/(cosA-sinA)+sin2A/(sinA-cosA)
=(sinAcosA-sin2A)/(cosA-sinA)
=sinA(cosA-sinA)/(cosA-sinA)
=sinA=R.H.S (make correction in problem statement)
Answered by | 23rd May, 2009, 03:41: PM
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