Prove
Asked by Sonal13 | 12th Jun, 2009, 04:25: PM
Expert Answer:
L.H.S.=1+cosA+sinA/1+cosA-sinA(Multiplying and dividing by 1+cosA+sinA)
=(1+cos2 A+sin2 A+2cosA+2cosAsinA+2sinA)/(1+cos2 A+2cosA-sin2 A)
=(2+2cosA+2cosAsinA+2sinA)/(2cos2 A+2cosA)=(2(1+cosA) +2sinA(1+cosA))/2cosA(1+cosA)=(1+sinA)/cosA
=R.H.S
Answered by | 13th Jun, 2009, 07:06: PM
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