CBSE Class 10 Answered
prove that
Asked by | 06 Jun, 2008, 07:30: PM
Expert Answer
tanA/(secA-1) + tanA/(secA+1)
= (sinA/cosA)/(1-cosA / cosA) + (sinA/cosA)/(1+cosA/cosA)
= sinA/(1-cosA) + sinA/(1+cosA)
= [sinA - sinAcosA + sinA + sinAcosA] / (1+cosA)(1-cosA)
= 2sinA/ 1-cos2A
= 2sinA/ sin2A
= 2/sinA
= 2CosecA
Answered by | 07 Jun, 2008, 08:18: PM
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