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CBSE Class 10 Answered

prove that
Asked by | 06 Jun, 2008, 07:30: PM
answered-by-expert Expert Answer

tanA/(secA-1) + tanA/(secA+1)

= (sinA/cosA)/(1-cosA / cosA) + (sinA/cosA)/(1+cosA/cosA)

= sinA/(1-cosA) + sinA/(1+cosA)

= [sinA - sinAcosA + sinA + sinAcosA] / (1+cosA)(1-cosA)

= 2sinA/ 1-cos2A

= 2sinA/ sin2A

= 2/sinA

= 2CosecA

Answered by | 07 Jun, 2008, 08:18: PM
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