prove that while refraction through a rectangular glass slab the incident ray is parallel to the emergent ray

Asked by  | 10th Mar, 2013, 06:32: PM

Expert Answer:

In triangle GBC,
so r1=r2
as n =sin i/sin r1 =sin r2/sin e    as r1=r2
so i=e
so for, CF and DE, and intercector CD
angle BCF=angle CDE=corresponding angle
so CF parallel to DE.

Answered by  | 11th Mar, 2013, 03:34: PM

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