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prove that while refraction through a rectangular glass slab the incident ray is parallel to the emergent ray
Asked by | 10 Mar, 2013, 06:32: PM
Expert Answer
In triangle GBC,
r1+90-r2=90
so r1=r2
as n =sin i/sin r1 =sin r2/sin e    as r1=r2
so i=e
so for, CF and DE, and intercector CD
angle BCF=angle CDE=corresponding angle
so CF parallel to DE.
Answered by | 11 Mar, 2013, 03:34: PM

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