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prove that the tangent at any point of a circle is perpendicular to the radius through the point of contact
Asked by muskanmahek2411 | 08 Oct, 2021, 10:48: PM
Given: A circle C (O, r) and a tangent AB at a point P.

### Given: A circle C (O, r) and a tangent AB at a point P.To Prove: OP is perpendicular to AB.Construction: Take any point Q, other than P, on the tangent AB. Join OQ.Since, Q is a point on the tangent AB, other than the point of contact P, so Q will be outside the circle.Let OQ intersect the circle at R.Then, OQ=OR+RQOQ>OROQ>OP (OR=OP=radius)Thus, OPBut, among all the line segments, joining the point O to a point on AB, the shortest one is the perpendicular from O on AB.Hence, OP is perpendicular to AB.Gi

Answered by Renu Varma | 23 Oct, 2021, 06:28: PM

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