Prove that the sum of the three altitudes of a triangle is less than the sum of the three sides of the triangle.
Asked by Topperlearning User | 11th Aug, 2017, 10:06: AM
Of all the line segments drawn to a given line, from a point not on the line, the perpendicular is the shortest,
AL < AB, BM < BC and CN < CA
Adding the above inequalities,
AL + BM + CN < AB + BC + CA
Hence, the sum of the altitudes is less than the perimeter of the triangle.
Answered by | 11th Aug, 2017, 12:06: PM
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