In the figure AD is the bisector of 
A, prove that AB > BD.
Asked by Topperlearning User | 11th Aug, 2017, 10:04: AM
Expert Answer:
AD is the bisector of A
BAD = CAD
Exterior BDA > CAD
BDA > BAD
AB > BD (side opposite the bigger angle is longer)
A BAD = CAD BDA > CADBDA > BADAB > BD (side opposite the bigger angle is longer) Answered by | 11th Aug, 2017, 12:04: PM
Related Videos
- show that in a right angle triagle the hypotenuse is the longest side
- What is the greatest possible perimeter of a right angeled triangle with integer sides lengths if one of the sides has length 12?
- Prove that the perimeter of a triangle is greater than the sum of its three medians.
- Prove that if two sides of a triangle are unequal, the longer side has greater angle opposite it.
- In the figure PQ > PR, QS and RS are the bisectors of
Q and R respectively. Prove that SQ > SR. 
- Prove that the sum of the three altitudes of a triangle is less than the sum of the three sides of the triangle.
- In the given figure, x > y. Show that LM > LN.
- Prove that in a right triangle, the hypotenuse is the longest side.
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change