CBSE Class 11-science Answered
prove that(sin8xcosx-sin6xcos3x)/(cos2x.cosx-sin4xsin3x)=tan 2x
Asked by nimisha varghese | 23 Aug, 2010, 12:00: AM
Expert Answer
L.H.S = (sin8xcosx-sin6xcos3x)/(cos2xcosx-sin4xsin3x)
Multiply numerator and denominator by 2
= (2sin8xcosx-2sin6xcos3x)/(2cos2xcosx-2sin4xsin3x)
Apply product to sum formulae
= [(sin9x + sin7x) - (sin 9x + sin3x)]/[(cos3x + cosx) -(cosx - cos 7x)]
= (sin7x - sin3x) / (cos3x + cos7x)
Apply sum to product formulae
= (2cos5xsin2x) / (2cos5xcos2x)
= tan2x = R.H.S
Answered by | 23 Aug, 2010, 09:44: PM
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