Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

Prove R=2f..!
Asked by Sneha George | 25 Feb, 2011, 03:03: AM
Expert Answer
Dear student

 

 

Consider a ray of light AB, parallel to the principal axis, incident on a spherical mirror at point B. The normal to the surface at point B is CB and CP = CB = R, is the radius of curvature. The ray AB, after reflection from mirror will pass through F (concave mirror) or will appear to diverge from F (convex mirror) and obeys law of reflection, i.e., i = r.

 

From the geometry of the figure,

 

 

 

If the aperture of the mirror is small, B lies close to P, \ BF = PF

 

or FC = FP = PF

 

or PC = PF + FC = PF + PF

 

or R = 2 PF = 2f

 

 

Similar relation holds for convex mirror also. In deriving this relation, we have assumed that the aperture of the mirror is small.

 

 

 

 

 

 

 

 

 

 

 

Hope this helps.

Regards

Team

Topperlearning

Answered by | 25 Feb, 2011, 10:06: AM
CBSE 10 - Physics
Asked by priyankakiran2017 | 22 Jun, 2022, 07:07: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by priyankakiran2017 | 21 Jun, 2022, 08:44: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by aarjugodara2 | 18 Jun, 2022, 04:36: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by priyankakiran2017 | 15 Jun, 2022, 03:26: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by vaishnavimishra2003 | 14 Jun, 2022, 07:45: AM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by officialnishantyadavji | 13 Jun, 2022, 01:09: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by priyankakiran2017 | 24 May, 2022, 06:36: PM
ANSWERED BY EXPERT

Start your hassle free Education Franchisee and grow your business!

Know more
×