Request a call back

Join NOW to get access to exclusive study material for best results

JEE Class main Answered

Plz tell me this in detailed the strategy being applied here 
question image
Asked by shrutigandha07 | 15 Apr, 2019, 20:40: PM
answered-by-expert Expert Answer
From second law of thermodynamics,
 
open parentheses fraction numerator increment straight T over denominator straight T subscript 1 end fraction close parentheses space equals space straight A over straight Q

straight A space equals open parentheses fraction numerator increment straight T over denominator straight T subscript 1 end fraction close parentheses straight Q

space space space space equals fraction numerator open parentheses 380 minus 280 close parentheses cross times 760 over denominator 380 end fraction

space space space space space equals 200 space kJ
760 - 200 = 560 kJ
 
Therefore,
(i) 650 kJ is irrevessible, (ii) 560 kJ is revesible and (iii) 404 kJ is impossible cycle.
Answered by Varsha | 16 Apr, 2019, 11:03: AM
JEE main - Chemistry
Asked by sgawade2310 | 26 Jun, 2021, 14:58: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
Asked by shrutigandha07 | 15 Apr, 2019, 20:40: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
Asked by vishakhachandan026 | 15 Apr, 2019, 11:34: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
Asked by g_archanasharma | 20 Feb, 2019, 18:04: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
Asked by g_archanasharma | 08 Feb, 2019, 17:49: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT