JEE Class main Answered

plz solve....it is from double titration

Asked by Dev | 02 Jun, 2019, 11:14: AM

Expert Answer

To neutralise whole Na₂CO_3, Volume of H₂SO₄ will be twice of given volume.

N a subscript 2 C O subscript 3 plus H to the power of plus rightwards arrow N a H C O subscript 3 space plus space N a to the power of plus N subscript 1 V subscript 1 equals N subscript 2 V subscript 2 N subscript 1 equals fraction numerator N subscript 2 V subscript 2 over denominator V subscript 1 end fraction space space N subscript 1 space equals fraction numerator left parenthesis 2 cross times 0.1 right parenthesis cross times left parenthesis 2 cross times 2 right parenthesis over denominator 10 end fraction equals 0.08 N space space space space W e i g h t space o f space N a subscript 2 C O subscript 3 space i n space 1 space L space space equals 0.08 cross times 53 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 4.24 g space space I n space 1 space L space w e i g h t space o f space space N a subscript 2 C O subscript 3 space equals 4.24 g space I n space 10 space m l space N a subscript 2 C O subscript 3 space w i l l space b e equals fraction numerator 4.24 over denominator 1000 end fraction cross times 10 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals.0424 space g space space space space space space space space space space space

Answered by Ravi | 03 Jun, 2019, 12:30: PM

Please Login or Sign up to continue!

JEE Class main Answered

Choose Filters

Open In Ask A Doubt App ?

Get in Touch