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plz solve
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Asked by swayamagarwal2114 | 21 Jul, 2022, 17:18: PM
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Pressure P is the force acting on unit area .If we consider a fluid element of small size dr , then pressure dp
 
due to this small element dr is given as
 
dp = ρ g(r) dr
 
where ρ is uniform density and g(r) is acceleration due to gravity at distance r
 
g(r) = G ( m / r2 )
 
where G is universal gravitation constant and m is mass of fluid in sphere of radius r.
 
begin mathsize 14px style g left parenthesis r right parenthesis space equals space G space fraction numerator begin display style 4 over 3 end style pi space r cubed space rho over denominator r squared end fraction space equals space 4 over 3 pi space G space rho space r end style
Presuure at centre due to full radius R is given as
 
begin mathsize 14px style P space equals space integral subscript 0 superscript R rho space g left parenthesis r right parenthesis space d r space equals space 4 over 3 pi space G space rho squared space integral subscript 0 superscript R r space d r space equals space space 2 over 3 pi space G space rho squared R squared end style
Answered by Thiyagarajan K | 21 Jul, 2022, 20:52: PM
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JEE main - Physics
Square of the time period of revolution of a planet is proportional to the cube of the mean distance between sun and planet. If mean distance is increased by 2% then percentage change in its time period is
Asked by coolskrish | 13 Oct, 2024, 12:50: PM
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JEE main - Physics
if the radius of the earth sinks by 1% and its density remain constant then what is the change in value of acceleration due to gravity of earth at its surface. Please solve it by using error concept, I have a little confusion in it.
Asked by srkgb8018 | 15 May, 2024, 20:12: PM
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JEE main - Physics
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Asked by anushkaracha | 14 Mar, 2024, 10:38: AM
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JEE main - Physics
Two identical metal spheres each of diameter 'd ' are kept in contact,then gravitational force is proportional to
Asked by krajasekharnaidu13 | 04 Feb, 2024, 15:37: PM
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JEE main - Physics
t
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Asked by jpmeena2222 | 31 Dec, 2023, 10:27: AM
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JEE main - Physics
Four particles of equal masses are moving round a circle of radius r due to their mutual gravitation attraction. Find the angular velocity.
Asked by aadityakumar0603 | 05 Mar, 2023, 22:17: PM
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JEE main - Physics
i just want to know why a ball falls on earth when left from a height becuse the gravitional forces of both of them is equal and opposite hence the ball must tend to be at rest in the air .I have already consulted few lecturers but their answer were complicated and tough to understand so i want to get a simpler answer so that i acn understand it in a proper way   
Asked by geethamehs08 | 15 Oct, 2022, 17:54: PM
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JEE main - Physics
.
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Asked by swayamagarwal2114 | 18 Aug, 2022, 09:04: AM
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JEE main - Physics
plz solve
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Asked by swayamagarwal2114 | 21 Jul, 2022, 17:18: PM
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JEE main - Physics
Sir,The gravitational due to a uniform disc at a point in its axis is 2GMr/R²((1/r)-(1/√(r²+R²))).Andthe potential at a point in the axis is -2GM/R²(√(R²+r²)-r) where R-radius and r-distance in the axis. Also,We know that on differentiating gravitational potential we get the gravitational field at that point.But that is not the case for disc.On integrating the potential we are not getting the value of the field.Why is it so? Please help
Asked by das.atom1966 | 16 May, 2022, 17:34: PM
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