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Asked by swayamagarwal2114 | 21 Jul, 2022, 05:18: PM
answered-by-expert Expert Answer
Pressure P is the force acting on unit area .If we consider a fluid element of small size dr , then pressure dp
 
due to this small element dr is given as
 
dp = ρ g(r) dr
 
where ρ is uniform density and g(r) is acceleration due to gravity at distance r
 
g(r) = G ( m / r2 )
 
where G is universal gravitation constant and m is mass of fluid in sphere of radius r.
 
begin mathsize 14px style g left parenthesis r right parenthesis space equals space G space fraction numerator begin display style 4 over 3 end style pi space r cubed space rho over denominator r squared end fraction space equals space 4 over 3 pi space G space rho space r end style
Presuure at centre due to full radius R is given as
 
begin mathsize 14px style P space equals space integral subscript 0 superscript R rho space g left parenthesis r right parenthesis space d r space equals space 4 over 3 pi space G space rho squared space integral subscript 0 superscript R r space d r space equals space space 2 over 3 pi space G space rho squared R squared end style
Answered by Thiyagarajan K | 21 Jul, 2022, 08:52: PM
JEE main - Physics
Asked by krajasekharnaidu13 | 04 Feb, 2024, 03:37: PM
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JEE main - Physics
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Asked by jpmeena2222 | 31 Dec, 2023, 10:27: AM
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JEE main - Physics
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Asked by swayamagarwal2114 | 18 Aug, 2022, 09:04: AM
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JEE main - Physics
Asked by swayamagarwal2114 | 21 Jul, 2022, 05:18: PM
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JEE main - Physics
Asked by bathularohith19 | 27 Mar, 2022, 03:05: PM
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JEE main - Physics
Asked by Amit | 21 Mar, 2019, 09:48: AM
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