Request a call back

Four particles of equal masses are moving round a circle of radius r due to their mutual gravitation attraction. Find the angular velocity. Expert Answer Figure shows four particles moving in a circular path due to gravitational force of attraction .

F1 is the force acting on each particle due to attraction by other particle that is diametrically opposite .

magnitude of F1 is where G is universal gravitationla constant , m is mass of each particle and r is radius of circular path.

F2 and F3 are the forces acting on each particl due to left side and right side neighbour.

Magnitude of F2 and F3 are equal . F2 and F3 each make angle 45o with F1 .

Hence resultant of F2 and F3 is in the same direction of F1 .  Magnitude of net force F acting on each particle is Above force F provides the centripetal force required for circular motion .

Centripetal force of circular motion equals gravitational force of attraction . Let ω be the angular speed of rotation of masses.  Answered by Thiyagarajan K | 06 Mar, 2023, 08:48: AM
JEE main - Physics ANSWERED BY EXPERT
JEE main - Physics
Asked by geethamehs08 | 15 Oct, 2022, 05:54: PM ANSWERED BY EXPERT
JEE main - Physics
. Asked by swayamagarwal2114 | 18 Aug, 2022, 09:04: AM ANSWERED BY EXPERT
JEE main - Physics
plz solve Asked by swayamagarwal2114 | 21 Jul, 2022, 05:18: PM ANSWERED BY EXPERT
JEE main - Physics
Asked by das.atom1966 | 16 May, 2022, 05:34: PM ANSWERED BY EXPERT
JEE main - Physics
Asked by bathularohith19 | 27 Mar, 2022, 03:05: PM ANSWERED BY EXPERT
JEE main - Physics
Asked by anshuman.anshuman090 | 07 Apr, 2019, 09:26: AM ANSWERED BY EXPERT
JEE main - Physics
Asked by Amit | 21 Mar, 2019, 09:48: AM ANSWERED BY EXPERT
JEE main - Physics
Q. Solve the question in photo Asked by Vidushi412 | 16 Mar, 2019, 12:27: PM ANSWERED BY EXPERT