PLZ SOLVE THIS
Asked by
| 8th Mar, 2008,
10:38: PM
Solution to your above question "SEVEN YEARS AGO VIVEK'S AGE WAS FIVE TIMES THE SQUARE OF SURESH'S AGE.THREE YEARS HENCE SURESH'S AGE WILL BE TWO-FIFTH'S OF VIVEK AGE.FIND THE PRESENT AGES OF VIVEK AND SURESH " is as follows:
Let Viveks age be x yrs
Suresh's age will be y yrs
ATQ (x-7) =5(y-7)2 (i)
(y+3) = 2/5(x+3) (ii)
(i) gives x = 5((y-7)2 +7
using it in (ii) we get
(y+3) = 2/5(5((y-7)2 +10)
y+3 = 2 y2-28y+102
So 2 y2-29y+99 =0
Solving we get y = 9 and 11/2
Age cannot be in fraction so y =9
And x =27
Answered by
| 10th Mar, 2008,
12:32: PM
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