PLZ SOLVE THIS

Solution to your above question "SEVEN YEARS AGO VIVEK'S AGE WAS FIVE TIMES THE SQUARE OF SURESH'S AGE.THREE YEARS HENCE SURESH'S AGE WILL BE TWO-FIFTH'S OF VIVEK AGE.FIND THE PRESENT AGES OF VIVEK AND SURESH " is as follows:

Let Viveks age be x yrs 
Suresh's age will be y yrs
 ATQ (x-7) =5(y-7)²     (i)
(y+3) = 2/5(x+3)           (ii) 
(i) gives x = 5((y-7)² +7
using it in (ii) we get
(y+3) = 2/5(5((y-7)² +10)
y+3 = 2 y²-28y+102
So 2 y²-29y+99 =0
Solving we get y = 9 and 11/2
Age cannot be in fraction so y =9 
And x =27