CBSE Class 10 Answered
plz hurry.......
Asked by khushal305 | 07 Jun, 2009, 07:50: PM
Expert Answer
In case we need to find out when exactly will hey meet again we can calculate their actual speeds as, 2 kmph,2.5 kmph,3 kmph.
Relative gain of second cyclist over first one is 0.5 km/h and that of fastest one is 1 km/h. Clearly 2nd will catch first in 360/0.5 h=720 h and 3rd will catch first in 360/1 h= 360 h. SImilarly, third will catch 2nd in 720 h.
Hence all of them will be simultanously at same point next after 720 h or 30 days.
Answered by | 08 Jun, 2009, 01:26: AM
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:53: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:13: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 04:59: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by ROJAAPPA | 29 May, 2010, 12:58: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 10:52: AM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by devanshmudgal | 28 May, 2010, 07:31: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:12: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:08: PM
ANSWERED BY EXPERT
