JEE Class main Answered
pls
Asked by ansarishayaan007 | 29 Dec, 2022, 18:03: PM
Expert Answer
It is assumed that direction of electric field is perpendicular to the surface and the surface is square of side 15 cm .
Electric flux = E × A
where E is electric field intensity and A is area of surface
Electric flux = 1.5 × 10-2 × 0.15 × 0.15 = 3.375 × 10-4 N C-1 m2
Answered by Thiyagarajan K | 29 Dec, 2022, 20:15: PM
JEE main - Physics
Asked by manishkanna555 | 07 Jul, 2024, 10:25: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by chandana9827 | 13 Jun, 2024, 20:28: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ratnadeep.dmr003 | 21 Apr, 2024, 23:06: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by medhamahesh007 | 02 Apr, 2024, 11:11: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by chhayasharma9494 | 31 Mar, 2024, 12:47: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by archithateja3 | 30 Mar, 2024, 22:23: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by mfkatagi099 | 20 Mar, 2024, 21:35: PM
ANSWERED BY EXPERT