pls solve

Asked by pb_ckt | 14th Jun, 2019, 11:19: PM

Expert Answer:

begin mathsize 16px style Given colon space straight A space plus space straight B space plus space straight C space equals space 180 degree
rightwards double arrow straight A space plus space straight B space equals space 180 degree space minus space straight C
rightwards double arrow tan open parentheses straight A space plus space straight B close parentheses equals space tan open parentheses 180 degree space minus space straight C close parentheses
rightwards double arrow fraction numerator tanA space plus space tanB over denominator 1 space minus space tanAtanB end fraction equals space minus tanC
rightwards double arrow tanA space plus space tanB space equals space minus tanC space plus space tanAtanBtanC
rightwards double arrow tanA space plus space tanB plus tanC space equals space space tanAtanBtanC space space... space left parenthesis straight i right parenthesis
To space find colon space fraction numerator tanA space plus space tanB plus tanC over denominator tanAtanBtanC end fraction space
From space left parenthesis straight i right parenthesis comma space we space get
fraction numerator tanA space plus space tanB plus tanC over denominator tanAtanBtanC end fraction equals tanAtanBtanC over tanAtanBtanC equals space 1
Correct space Option space colon space straight C end style

Answered by Yasmeen Khan | 15th Jun, 2019, 10:37: PM