Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

Pls solv follin

Asked by ntg432000 | 22 May, 2019, 08:10: PM
Expert Answer
In formation of negatively charged colloidal [AgI]I-
Ag comes from AgNo3 and Iodine comes from KI.This is negative sol so I - which comes from KI should have more number of moles than AgNO and two moles of KI are required for one mole of AgNO3 (one for AgI and one for I- ). So we can say number of moles of KI should be double of number of moles of AgNO3.
left parenthesis 1 right parenthesis Number space of space moles space of space AgNO subscript 3 equals 50 cross times 1 cross times 10 to the power of negative 3 end exponent equals 50 cross times 10 to the power of negative 3 end exponent space space left parenthesis moles equals straight M cross times straight V left parenthesis in space straight L right parenthesis right parenthesis
space space space space space Number space of space moles space of space space KI equals 50 cross times 1.5 cross times 10 to the power of negative 3 end exponent equals 75 cross times 10 to the power of negative 3 end exponent

left parenthesis 2 right parenthesis space Number space of space moles space of space AgNO subscript 3 equals 50 cross times 1 cross times 10 to the power of negative 3 end exponent equals 50 cross times 10 to the power of negative 3 end exponent
space space space space space Number space of space moles space of space space KI equals 50 cross times 2 cross times 10 to the power of negative 3 end exponent equals 100 cross times 10 to the power of negative 3 end exponent

left parenthesis 3 right parenthesis right parenthesis Number space of space moles space of space AgNO subscript 3 equals 50 cross times 2 cross times 10 to the power of negative 3 end exponent equals 100 cross times 10 to the power of negative 3 end exponent
space space space space space Number space of space moles space of space space KI equals 50 cross times 1.5 cross times 10 to the power of negative 3 end exponent equals 75 cross times 10 to the power of negative 3 end exponent

left parenthesis 4 right parenthesis space Number space of space moles space of space AgNO subscript 3 equals 50 cross times 1 cross times 10 to the power of negative 3 end exponent equals 50 cross times 10 to the power of negative 3 end exponent
space space space space space Number space of space moles space of space space KI equals 50 cross times 1 cross times 10 to the power of negative 3 end exponent equals 50 cross times 10 to the power of negative 3 end exponent
 
So option 2 is correct answer.
Answered by Ravi | 23 May, 2019, 04:58: PM
CBSE 12-science - Chemistry
Asked by ntg432000 | 22 May, 2019, 08:10: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by niharikapabba2605 | 07 Aug, 2018, 11:39: AM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by Topperlearning User | 21 Jun, 2016, 12:32: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
×