CBSE Class 12-science Answered
From the given information , Table given below is made for the score of TeamX and Team y in three components
Component | Score of Team X | Score of Team Y |
Precession Navigation | 40 | 133 |
Obstacle Avoidance | 1.875 × 40 = 75 | 45 |
Speed Challenge | 25+a | a |
140+a | 178+a |
Team X got the score 40 in Precession navigation . Team Y got the score of 45 in Obstacle Avoidance.
These scores are entered in the table that can be seen in the above table.
Let a is the score of Team Y in speed challenge . Team X got 25 points more than Team Y in speed challenge.
These scores are entered in the table for both the teams .
Team X got 87.5 % more score in Obstacle avoidance than its own score of Precession Navigation .
Hence score of team X in Obstacle avoidance is ( 40 + 0.875 × 40 ) = 75 .
Score of team Y in Precession Navigation is 2 less than thrice of its own score in Obstacle avoidance.
Hence score of team Y in Precession Navigation is ( 3 × 45 - 2 ) = 133
Total score of team X = 40 +75+(25+a) = 140 + a ....................... (1)
Total score of team Y = 133 + 45 + a = 178 + a .......................... (2)
Total score of both the teams = 140+a + 178+a = 318+2a ...............(3)
If total score of team X is 45% of total score of both the teams , then
140 +a = 0.45 × ( 318+ 2a)
By solving above expression, we get a = 31
Hence score of Team X in speed challenge = (25+31) = 56
Score of Team Y in speed challenge = 31
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Qn. # 115
Total score of team X as given by eqn.(1) is 140 +31 = 171
Qn. # 116
Total score of team X and team Y in speed challenge , ( 56 + 31 ) = 87
Qn. # 117
Absolute difference between scores of team X and team Y in
Precession navigation is ( 133-40 ) = 93