CBSE Class 12-science Answered

solution for the given problems

Asked by sankarbongu2003 | 22 Jun, 2020, 11:18: AM

Expert Answer

To find the domain of f(x) where it is given as

straight f left parenthesis straight x right parenthesis equals fraction numerator straight x minus 3 over denominator open parentheses straight x plus 3 close parentheses square root of straight x squared minus 4 end root end fraction straight f left parenthesis straight x right parenthesis space is space defined space if space open parentheses straight x plus 3 close parentheses square root of straight x squared minus 4 end root not equal to 0 straight x not equal to negative 3 space and space square root of straight x squared minus 4 end root not equal to 0 square root of straight x squared minus 4 end root space is space defined space when space straight x squared minus 4 greater than 0 rightwards double arrow left parenthesis straight x minus 2 right parenthesis left parenthesis straight x plus 2 right parenthesis greater than 0 rightwards double arrow straight x minus 2 greater than 0 space and space straight x plus 2 greater than 0 space space OR space space straight x minus 2 less than 0 space and space straight x plus 2 less than 0 rightwards double arrow straight x greater than 2 space and space straight x greater than negative 2 space space OR space space straight x less than 2 space and space straight x less than negative 2 rightwards double arrow straight x greater than 2 space space OR space space straight x less than negative 2 rightwards double arrow straight x element of left parenthesis 2 comma space infinity right parenthesis space space OR space space straight x element of left parenthesis negative infinity comma space minus 2 right parenthesis rightwards double arrow straight x element of left parenthesis negative infinity comma space minus 2 right parenthesis union left parenthesis 2 comma space infinity right parenthesis Hence comma space the space domain space of space straight f left parenthesis straight x right parenthesis space is space left parenthesis negative infinity comma space minus 2 right parenthesis union left parenthesis 2 comma space infinity right parenthesis minus left curly bracket 3 right curly bracket

Answered by Renu Varma | 22 Jun, 2020, 12:01: PM

CBSE Class 12-science Answered

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