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Pls answer fast... In a resistive circuit, if the current is increased to two times the percentage change in the amount of heat dissipated in the circuit would be a) 400% b) 300% c) 200% d) 100%
Asked by anubhutiupadhaya | 04 Mar, 2023, 03:16: PM
answered-by-expert Expert Answer
Heat dissipated in circuit is directly proportional to square of current and resistance. 
According to Joule's law of heating, 
H =I2Rt ...(1)
If current is increased to two times, 
Heat dissipated H' = (2I)2 Rt = 4I2Rt ...(2) 
 
Thus, 
percentage change in amount of heat dissipated will be, 
 
 percent sign space c h a n g e space i n space h e a t space d i s s i p a t e d space equals space open parentheses fraction numerator H apostrophe minus H over denominator H end fraction close parentheses cross times 100 equals open parentheses fraction numerator 4 I squared R t space minus space I squared R t over denominator I squared R t end fraction close parentheses cross times 100 equals fraction numerator 3 left parenthesis I squared R t right parenthesis over denominator left parenthesis I squared R t right parenthesis end fraction cross times 100 equals 3 cross times 100 space equals 300  
 
Correct option -> b) 300%
Answered by Shiwani Sawant | 04 Mar, 2023, 03:28: PM

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CBSE 10 - Physics
Pls answer fast... In a resistive circuit, if the current is increased to two times the percentage change in the amount of heat dissipated in the circuit would be a) 400% b) 300% c) 200% d) 100%
Asked by anubhutiupadhaya | 04 Mar, 2023, 03:16: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
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