CBSE Class 10 Answered
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![question image](https://images.topperlearning.com/topper/new-ate/31936675468436205IMG20180530190545.jpg)
Asked by riyamaths | 30 May, 2018, 19:16: PM
Let RA be the resistance of wire-A and is given by
![begin mathsize 12px style R subscript A equals rho fraction numerator L over denominator pi cross times r squared end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/359ce3f5f33482b45114a3fbdb820f18.png)
where ρ is resitivity, L is length and r is radius.
Let RB be the resistance of wire-B and it is given by
![begin mathsize 12px style R subscript B equals rho fraction numerator 2 L over denominator pi cross times 4 cross times r squared end fraction space equals R subscript A over 2 end style](https://images.topperlearning.com/topper/tinymce/cache/783f8c4008c151c8839d3b547a17e255.png)
Equivalent resistance Req of parallel combinaion is given by
![begin mathsize 12px style R subscript e q end subscript equals space fraction numerator R subscript A cross times R subscript B over denominator R subscript A plus R subscript B end fraction space equals space fraction numerator R subscript A cross times begin display style R subscript A over 2 end style over denominator R subscript A plus begin display style R subscript A over 2 end style end fraction space equals space R subscript A over 3 end style](https://images.topperlearning.com/topper/tinymce/cache/bfa72398686cc83f0e0255a7f61b98e8.png)
hence the required ratio is 1/3
Answered by Thiyagarajan K | 31 May, 2018, 12:33: PM
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