Please solve this question 🙏

8 × 2^2x + 4 × 2^{x + 1} = 1 + 2^x

8 × 2^2x + 4 × 2^x × 2 = 1 + 2^x

Let 2^x = m

8m² + 8m = 1 + m

8m² + 7m - 1 = 0

Solving this using factorisation we get

(m + 1)(8m - 1) = 0

m = -1 or m = 1/8

2^x = -1 or 2^x = 2^-3 

As 2^x ≠ -1 hence, 2^x = 2^-3 then x = -3