CBSE Class 12-science Answered
Please solve the following question using Kirchoff's current law and Kirchoff's voltage law asap. :))
Asked by mfirdous111 | 24 Nov, 2020, 12:05: AM
Expert Answer
Figure shows the current passing through each resistor.
Since all resistors are in kΩ, we consider all currents in mA
By applying Kirchoff's voltage law (KVL) we get , 8 I1 + 4 I2 = 12 V or 2 I1 + I2 = 3 .....................(1)
In loop-2, by applying KVL , we get , 10 I4 + 5 I5 = 4 I2 ..................(2)
In loop-3 , by applying KVL , we get , 18 I7 = 5 I5 ........................(3)
At node-Q , if we apply Kirchoff's Current law ( KCL ) , we get , I4 = I5 + I7 ...............(4)
Using eqn.(4) and eqn.(3), we rewrite eqn.(2) as 10 I5 + 28 I7 = 4 I2 ...................(5)
Using eqn.(3) , we rewrite eqn.(5) as , 64 I7 = 4 I2 or I7 = (1/16) I2 .................(6)
Using eqn.(3) , we get I5 = (18/5) I7 = (18/5) (1/16) I2
Hence we get I5 = (9/40) I2 ...........................(7)
From eqn.(4), we get , I4 = [ (9/40) + (1/16) ] I2 = (23/80) I2 .......................(8)
At node-P , if we apply Kirchoff's Current law ( KCL ) , we get , I1 = I2 + I4 ...............(9)
Let us rewrite eqn.(1) , using eqn.(9) as , 3I2 + 2I4 = 3
3 I2 + 2 (23/80) I2 = ( 143/40 ) I2 = 3 or I2 = ( 120/143 ) = 0.839 mA .....................(10)
Hence from eqn.(1) , we get I1 = (3/2) - (1/2) I2 = (3/2) - (1/2)(0.839) = 1.080 mA ................(11)
Current I4 = (23/80) ( 0.839) = 0.241 mA
Current I5 = (9/40) ( 0.839) = 0.189 mA
Current I7 = (1/16) (0.839) = 0.052 mA
By knowing all the currents passing in the circuit , it is possible to get voltage across each resistor.
Answered by Thiyagarajan K | 24 Nov, 2020, 10:41: AM
Concept Videos
-
Electric Charge - Part 1
This video describes the concept of charge, conductors and insulators, and ... -
Gold Leaf Electroscope - Part 1
This video explains the basic properties of electric charges. -
Coulom's Law of Electric Force - Part 1 ...
This video describes Coulomb's law to calculate the force between any two p... -
All about electric fields
Define electric field in terms of Coulomb's force. Apply superposition prin... -
Electric Field Lines
This video explains the representation of electric field due to a single ch...
CBSE 12-science - Physics
Asked by ankush76728 | 06 May, 2024, 04:52: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by ankush76728 | 05 May, 2024, 09:55: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by heymindurownbusiness | 04 May, 2024, 11:15: AM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by talulu | 01 May, 2024, 05:14: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by kanishkg511 | 30 Apr, 2024, 07:25: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by sahoobanita89 | 30 Apr, 2024, 05:10: AM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by divakar.9124 | 27 Apr, 2024, 10:42: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by panneer1766 | 24 Apr, 2024, 01:52: PM
ANSWERED BY EXPERT
