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CBSE Class 10 Answered

please solve question no 25
Asked by sg1929771 | 04 Jan, 2020, 07:24: PM
Expert Answer
p2 x2 + (p2 - q2)x - q2 = 0
Where a = p2, b = (p2 - q2) and c = -q2
b2 - 4ac = (p2 - q2)2 - 4p2(-q2)
= p4 - 2p2q2 + q4 + 4p2q2
= p4 + 2p2q2 + q4
= (p2 + q2)2
x = (-b ± √b2 - 4ac)/2a
x = [-(p2 - q2) ± (p2 + q2)]/2p2
Solving this we get q2/p2 or -1
Answered by Sneha shidid | 05 Jan, 2020, 12:27: AM

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