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CBSE Class 10 Answered

please solve for me..........
Asked by | 13 Dec, 2009, 09:18: PM
answered-by-expert Expert Answer

I hope  this 0 is theta θ   since cosec 0 is not defined

(secθ+cosecθ)(sinθ+cosθ)=2+secθ+cosecθ

Consider LHS

(1/cos θ + 1/sin θ ) (sinθ+cosθ) =   (sinθ+cosθ)/ sin  θ cos  θ

= (sin2 θ+cos2 θ+2sin θcos θ)/ sin  θ cos  θ

= sec θ cosec  θ  +2

Answered by | 14 Dec, 2009, 09:23: AM
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