please help Mee

Asked by deathkiller9875 | 13th Jun, 2022, 08:14: PM

Expert Answer:

Decompostion of CaCO3 takes place as-
CaCO subscript 3 space rightwards arrow CaO space plus space CO subscript 2

Molar space mass space of space CaCO subscript 3 space equals space 100 space straight g divided by mol
Molar space mas space of space CO subscript 2 equals 44 space straight g divided by mol

According space to space Stoichiometry comma space

100 space straight g space of space CaCO subscript 3 space produces space equals space 44 space straight g space of space CO subscript 2

1 space straight g space of space CaCO subscript 3 space will space produce space equals space 44 over 100 space straight g space of space CO subscript 2

straight x space straight g space of space pure space CaCO subscript 3 space wil space produce equals 44 over 100 space cross times straight x space space space straight g space of space CO subscript 2

44 over 100 space cross times straight x space space equals space 200 space left parenthesis given right parenthesis
straight x equals 200 over 44 cross times 100
straight x equals 4.54 cross times 100
straight x equals 454 space straight g

Which space means space out space of space 500 space straight g space of space CaCO subscript 3 space comma space Only space 454 space straight g space is space pure.

P e r c e n t a g e space P u r i t y equals space 454 over 500 cross times 100 equals 90.8 percent sign

Answered by Ravi | 16th Jun, 2022, 11:39: AM