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CBSE Class 11-science Answered

please help Mee
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Asked by deathkiller9875 | 13 Jun, 2022, 20:14: PM
answered-by-expert Expert Answer
Decompostion of CaCO3 takes place as-
CaCO subscript 3 space rightwards arrow CaO space plus space CO subscript 2 Molar space mass space of space CaCO subscript 3 space equals space 100 space straight g divided by mol Molar space mas space of space CO subscript 2 equals 44 space straight g divided by mol According space to space Stoichiometry comma space 100 space straight g space of space CaCO subscript 3 space produces space equals space 44 space straight g space of space CO subscript 2 1 space straight g space of space CaCO subscript 3 space will space produce space equals space 44 over 100 space straight g space of space CO subscript 2 straight x space straight g space of space pure space CaCO subscript 3 space wil space produce equals 44 over 100 space cross times straight x space space space straight g space of space CO subscript 2 44 over 100 space cross times straight x space space equals space 200 space left parenthesis given right parenthesis straight x equals 200 over 44 cross times 100 straight x equals 4.54 cross times 100 straight x equals 454 space straight g Which space means space out space of space 500 space straight g space of space CaCO subscript 3 space comma space Only space 454 space straight g space is space pure. P e r c e n t a g e space P u r i t y equals space 454 over 500 cross times 100 equals 90.8 percent sign
Answered by Ravi | 16 Jun, 2022, 11:39: AM

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