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Please help me solving electrophilic aromatic substitution reaction's ques. Ques. 11 of first pic. Ques. 3 of 2nd pic. Ques. 2 of third pic. Please solve all three with detailed mechanism. It won't take much time. Please help. ThanQ!
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Asked by jhajuhi19 | 29 Mar, 2020, 11:19: AM
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Ans. 10
For ethyl benzoate, the aromatic ring has a -CO2CH2CH3 group attached which is an electron withdrawing group. Therefore the electrophilic aromatic substitution reaction will occur at the meta position giving 3-nitrophenyl ethanoate.
 
Ans. 11
A rate of Iodination of benzenes and hexadeuteriobenzene are different because C-D bond is stronger than C-H bond since mass of deuterium is twice that of hydrogen which gives strength in bonding.
Hence, K1>K2
 
Ans.12
Similarly as Ans.10, CN is an deactivating group hence the product obtained is metachlorocynobenzene.
 
Answered by Ramandeep | 29 Mar, 2020, 21:03: PM
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Asked by hemeshsaini2005 | 11 Oct, 2021, 18:13: PM
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Asked by yasharthshankar | 30 Jun, 2020, 23:13: PM
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Asked by mdfaraz1182 | 09 Apr, 2020, 11:10: AM
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JEE main - Chemistry
Please help me solving electrophilic aromatic substitution reaction's ques. Ques. 11 of first pic. Ques. 3 of 2nd pic. Ques. 2 of third pic. Please solve all three with detailed mechanism. It won't take much time. Please help. ThanQ!
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Asked by jhajuhi19 | 29 Mar, 2020, 11:19: AM
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JEE main - Chemistry
Electrophilic aromatic substitution ques10. please explain both with detailed mechanism.   ThanQ!
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Asked by vidyavikram10 | 29 Mar, 2020, 11:09: AM
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JEE main - Chemistry
Sir, pls solve the following.
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Asked by rsudipto | 24 Dec, 2018, 09:02: AM
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