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NEET Class neet Answered

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Asked by Prashant DIGHE | 25 Feb, 2020, 22:10: PM
answered-by-expert Expert Answer
The given reaction is the test for chloride ion.
Chloride ion on treatment with dil. NaOH then dil.HNO3 after that on addition of silver nitrate it gives white ppt of silver chloride (AgCl).
Hence option 1 is omitted.
 
Now in option two has benzyl chloride and option 3 has chloro benzene, out of these two only option two will reats with NaOH and then rest of reagents. 
the reaction proceeds as follows:
 
straight C subscript 6 straight H subscript 5 minus CH subscript 2 minus Cl rightwards arrow with space space space space aq. NaOH space space space space on top straight C subscript 6 straight H subscript 5 minus CH subscript 2 minus OH rightwards arrow with space space space dil. HNO subscript 3 space space space on top straight C subscript 6 straight H subscript 5 minus CHO comma space white space ppt space of space AgCl space is space obtained
Answered by Ramandeep | 26 Feb, 2020, 15:19: PM
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