Permutations and combinations

JEE Class main Answered

Permutations and combinations

Asked by navyaankita121993 | 08 Feb, 2021, 08:40: PM

Expert Answer

It is given that a_k does not have k element as a permutation.

It has 5 elements each with 2 possibilities (one of being the permutation and the other of not being the permutation).

So for each 5 elements 1, 2, 3, 4, 5, there are 2 possibilities.

Hence, the total number of permutations possible is 6! - ⁶C₁ x 2⁵ = 528

Since $a_{k}$ does not have $k$ element as a permutation, it has $5$ elements each with 2 possibilities (one of being in the permutation and the other of not being the permutation). Hence, total permutations possible are

Answered by Renu Varma | 09 Feb, 2021, 12:30: PM

Answered Unanswered My Questions My Answers

JEE main - Maths

if all the letters of the word queue are arranged in all the possible manner as they are in a dictionary then the rank of the word queue is(by short cut method)

Asked by shivanshij5 | 07 Feb, 2024, 11:16: AM

ANSWERED BY EXPERT

JEE main - Maths

kya answer hoga

Asked by adhyayanbabu | 04 Dec, 2023, 09:49: PM

ANSWERED BY EXPERT

JEE main - Maths

7!/2! = 21 6!/2! = 15 how that ?

Asked by harshpunia109 | 26 Jun, 2023, 07:21: PM

ANSWERED BY EXPERT

JEE main - Maths

If all the permutation of the word DISCRETE are arranged in a dictionary order, then what will be the rank of DISCRETE.

Asked by harshpunia109 | 25 Jun, 2023, 06:36: PM

ANSWERED BY EXPERT

JEE main - Maths

Asked by krrishgarg967 | 07 Jan, 2023, 11:31: PM

ANSWERED BY EXPERT

JEE main - Maths

(A) 72 993. How many five-digit even numbers can be formed from the dights, 2,3,4,7 and 8, the digs are not repeated O (8) 36 © (c) 120 O (0) 54

Asked by abhishekssstays | 17 Dec, 2022, 05:00: PM

ANSWERED BY EXPERT

JEE main - Maths

velocity

Asked by varshitchouhan8 | 08 May, 2022, 08:48: PM

ANSWERED BY EXPERT

JEE main - Maths

number of ways of selecting three consecutive objects out of 15 objects distinct place around a circle

Asked by amadhusudhan09 | 28 Oct, 2021, 07:20: PM

ANSWERED BY EXPERT

JEE main - Maths

7c1

Asked by panchalbhavesh372 | 16 May, 2021, 10:50: AM

ANSWERED BY EXPERT

JEE main - Maths

Permutations and combinations

Asked by navyaankita121993 | 08 Feb, 2021, 08:40: PM

ANSWERED BY EXPERT

Please Login or Sign up to continue!

JEE Class main Answered

Since a k​ does not have k element as a permutation, it has 5 elements each with 2 possibilities (one of being in the permutation and the other of not being the permutation). Hence, total permutations possible are

Choose Filters

Open In Ask A Doubt App ?

Get in Touch

Call / Whats App

Since $a_{k}$ does not have $k$ element as a permutation, it has $5$ elements each with 2 possibilities (one of being in the permutation and the other of not being the permutation). Hence, total permutations possible are