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Asked by krrishgarg967 | 07 Jan, 2023, 11:31: PM
answered-by-expert Expert Answer
begin mathsize 14px style P presuperscript n subscript r space equals space scriptbase p subscript r plus 1 end subscript end scriptbase presuperscript n end style
begin mathsize 14px style fraction numerator n factorial over denominator left parenthesis n minus r right parenthesis factorial end fraction space equals space fraction numerator n factorial over denominator left parenthesis n space minus space r space minus 1 space right parenthesis factorial end fraction end style
 
begin mathsize 14px style fraction numerator left parenthesis n minus r minus 1 right parenthesis factorial over denominator left parenthesis space n space minus r space space right parenthesis factorial end fraction space equals space fraction numerator 1 over denominator left parenthesis n minus r right parenthesis end fraction space equals space 1 end style
 
Hence ( n-r) = 1  
 
begin mathsize 14px style C presuperscript n subscript r space equals space C presuperscript n subscript r minus 1 end subscript end style
 
begin mathsize 14px style fraction numerator n factorial over denominator left parenthesis n minus r right parenthesis factorial space r factorial end fraction space equals space fraction numerator n factorial over denominator left parenthesis n minus r plus 1 right parenthesis factorial space left parenthesis r minus 1 right parenthesis factorial end fraction end style
 
if we use the substitution (n-r) = 1, then we get
 
begin mathsize 14px style 2 space cross times space fraction numerator left parenthesis space r space minus 1 space right parenthesis factorial over denominator r space factorial end fraction space equals space 2 over r space equals space 1 end style
i.e., r = 2
 
if ( n-r) = 1 , then n = 3
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