Permutation and combination
Asked by NikhilD | 14th Apr, 2010, 11:28: AM
As we can see 8 are unmarried people, and 2 are married to each other, and since the married couple refuses to attend seperately, the total invitations are 9.
If the couple is excluded she has to select 5 people from 8, so 8C5.
If the couple is included she has to select 3 people from 8, so 8C3.
Hence the total number of ways = 8C5 + 8C3 = 56 + 56 = 112.
Answered by | 14th Apr, 2010, 04:26: PM
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