p(n):n2+n+41 is a prime number for n+1,2....40.The least no.for which the result does not hold is? a) 47 b)51 c)41 d)42

Asked by Mihir Date | 15th Mar, 2011, 12:00: AM

Expert Answer:

Dear Student,
Here is the solution for the problem:-
Since we are given 4 options we can go by the options
the function of prime number is P(n) = n2+n+41, chosing the smallest number from the given options we have
P(41) = 412+41+41 = 41(41+1+1) = 41.43 = which is not a prime number hence the answer is 41.
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Answered by  | 19th Mar, 2011, 11:33: PM

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