CBSE Class 12-science Answered
Optics
Asked by | 13 Jan, 2010, 11:25: PM
Expert Answer
Dear Student
If f is the focal length of lence and
When the lence is kept in the first position to get hte image
u1, v1 are distances of object and image from lence respectively
f= u1v1/(u1+v1)-----(1)
inthe second case u=u1+20, v= v1-20
so f= (u1+20)( v1-20) /( u1+20 + v1-20) =[u1v1-400-20u1+20v1]/ (u1+v1)----(2)
Equate qquations 1&2
==>u1=v1+20 ----(3)
but we have u1+v1=60 ---(4)
From Equations 3,4 ===> u1= 40, v1=20
Equn (1)==> f= 800/ 60 =13.33 cm
Regards
Team
Topperlearning
Answered by | 14 Jan, 2010, 11:27: AM
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