numerical

Asked by manu p.prakash | 23rd Feb, 2012, 04:18: PM

Expert Answer:

Ig=5% of I=0.05I S=IgxG/I-Ig=0.05IG/I-0.05I= 0.05I * 38 /0.95 I S = 0.05 * 38/ 0.95 = 2 ohms

Answered by  | 1st Mar, 2012, 04:54: PM

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