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CBSE Class 12-science Answered

  Find space the space derivative space of space sin to the power of minus 1 end exponent open parentheses straight e to the power of minus straight x end exponent close parentheses space with space respect space to space straight x
Asked by Topperlearning User | 01 Aug, 2014, 12:45: PM
Expert Answer

 Let space straight y equals sin to the power of minus 1 end exponent left parenthesis straight e to the power of minus straight x end exponent right parenthesis therefore dy over dx equals fraction numerator 1 over denominator square root of 1 minus left parenthesis straight e to the power of minus straight x end exponent right parenthesis squared end root end fraction left parenthesis minus straight e to the power of minus straight x end exponent right parenthesis equals fraction numerator minus straight e to the power of minus straight x end exponent over denominator square root of 1 minus straight e to the power of minus 2 straight x end exponent end root end fraction  

Answered by | 01 Aug, 2014, 02:45: PM

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