mid term exam

Asked by  | 24th Oct, 2009, 10:27: AM

Expert Answer:

sec 5A=cosec (A-36)=sec[90-(A-36)]=sec[54-A]

so we have

sec5A=sec[54-A]

cos 5A= cos (54-A)

use formula for  solutions of trigonometric  equation to solve.

Answered by  | 25th Oct, 2009, 10:15: AM

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