mid term exam
Asked by | 24th Oct, 2009, 10:27: AM
Expert Answer:
sec 5A=cosec (A-36)=sec[90-(A-36)]=sec[54-A]
so we have
sec5A=sec[54-A]
cos 5A= cos (54-A)
use formula for solutions of trigonometric equation to solve.
Answered by | 25th Oct, 2009, 10:15: AM
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