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Make full explanation with suitable formulae 
question image
Asked by vishakhachandan026 | 12 Apr, 2019, 04:24: PM
answered-by-expert Expert Answer
Option (3) is correct.
 
Given:
 
Cell reaction,
 
straight M space plus space 3 Ag to the power of plus space space rightwards arrow space straight M to the power of 3 plus end exponent plus space space 3 Ag subscript open parentheses straight s close parentheses end subscript space straight E space equals space straight E to the power of 0 minus space fraction numerator 0.0591 over denominator straight n end fraction space log fraction numerator open square brackets Red space state close square brackets over denominator open square brackets Oxd space state close square brackets end fraction 0.421 equals space space straight E to the power of 0 minus space fraction numerator 0.0591 over denominator 3 end fraction space log fraction numerator 0.001 over denominator open parentheses 0.01 close parentheses cubed end fraction space space space space straight E to the power of 0 space equals space 0.48 space space space space straight E to the power of 0 space equals space space space space straight E to the power of 0 subscript bevelled Ag to the power of plus over Ag end subscript space minus space space space space straight E to the power of 0 subscript bevelled straight M to the power of 3 plus end exponent over straight M end subscript space space space space space space space space space equals space 0.8 space equals 0.48 space space space space space straight E to the power of 0 space equals space 0.32 space volt
 
Standard potential is 0.32 V.
 
Answered by Varsha | 15 Apr, 2019, 11:57: AM

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