Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

Linear Equations in two variables
Asked by aruni_maiyer | 16 May, 2010, 03:51: PM
answered-by-expert Expert Answer

As shown below this example is an example of quadratic equation and variables are 3, so can't be solved UNLESS THE SCHEDULED TIME OF THE TRAIN IS GIVEN.

Let U be the uniform speed and T be regular time.

then the distance is D = UT.

If U + 6, then T - 4,

and U - 6, then T + 6,

But the product would still be the same distance, as the distance can't change.

(U+6)(T-4) = (U-6)(T+6)

UT -4U + 6T - 24 = UT + 6U - 6T - 36

10U - 12T - 12 = 0

10U - 12D/U - 12 = 0

10U2 - 12D - 12U = 0

Regards,

Team,

TopperLearning.

Answered by | 17 May, 2010, 07:39: AM
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:53: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:13: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by 2806rahul | 30 May, 2010, 09:28: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 04:59: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by ROJAAPPA | 29 May, 2010, 12:58: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 11:59: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 10:52: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by devanshmudgal | 28 May, 2010, 07:31: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:12: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:08: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×