Linear Equations in two variables
Asked by aruni_maiyer | 16th May, 2010, 03:51: PM
As shown below this example is an example of quadratic equation and variables are 3, so can't be solved UNLESS THE SCHEDULED TIME OF THE TRAIN IS GIVEN.
Let U be the uniform speed and T be regular time.
then the distance is D = UT.
If U + 6, then T - 4,
and U - 6, then T + 6,
But the product would still be the same distance, as the distance can't change.
(U+6)(T-4) = (U-6)(T+6)
UT -4U + 6T - 24 = UT + 6U - 6T - 36
10U - 12T - 12 = 0
10U - 12D/U - 12 = 0
10U2 - 12D - 12U = 0
Answered by | 17th May, 2010, 07:39: AM
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