Kindly provide proper and complete solution with a plausible explanation.

Asked by Varsneya Srinivas | 1st Mar, 2018, 08:02: AM

Expert Answer:

Force on plate-γ = Q×[ σ/(2εo) ] Newton;
Where Q is the charge on plate-γ and σ is the charge density on plate-β.
 
σ = q/S, where q is the charge on plate-β and A is the surface area of that plate
 
Force on plate-γ = Q×[ q/(S×2εo) ] Newton;
 
(2) Charegs on plate-β and plate-γ remains same, i.e. q and Q
 
(3) to get the velocity we use the equation of motion " v2 = u2+2aS ", with initial velocity u =0;
 
acceleration a = Force/mass = Q×[ q/(S×m×2εo) ] ; m is mass of plate-γ;
 
hence velocity = square root of ( 2 × Q×[ q/(S×m×2εo) ]×d )

Answered by Thiyagarajan K | 1st Mar, 2018, 01:54: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.