Kindly provide proper and complete solution with a plausible explanation.

Force on plate-γ = Q×[ σ/(2ε_o) ] Newton;

Where Q is the charge on plate-γ and σ is the charge density on plate-β.

 

σ = q/S, where q is the charge on plate-β and A is the surface area of that plate

 

Force on plate-γ = Q×[ q/(S×2ε_o) ] Newton;

 

(2) Charegs on plate-β and plate-γ remains same, i.e. q and Q

 

(3) to get the velocity we use the equation of motion " v² = u²+2aS ", with initial velocity u =0;

 

acceleration a = Force/mass = Q×[ q/(S×m×2ε_o) ] ; m is mass of plate-γ;

 

hence velocity = square root of ( 2 × Q×[ q/(S×m×2ε_o) ]×d )